Card

Eloise, Nephalia Sleuth

Mana cost {3}{U}{B}

Legendary Creature — Human Rogue 4/4

Whenever another creature you control dies, investigate. (Create a Clue token. It's an artifact with "{2}, Sacrifice this token: Draw a card.") Whenever you sacrifice a token, surveil 1. (Look at the top card of your library. You may put that card into your graveyard.)

Part of 120 known combos, one of them two-card. 3 official rulings.

Commander
Legal
Printing
Mythic · MIC · #3
Cheapest printing
€0.32
EDHREC salt
0.26
Color identity
Black, Blue
Keywords
Surveil, Investigate

Scryfall · EDHREC

Bracket

  • B1 Exhibition — Not in the same deck as its two-card combo partner: March of the Machines
  • B2 Core — Not in the same deck as its two-card combo partner: March of the Machines
  • B3 Upgraded — Not in the same deck as its early two-card combo partner: March of the Machines
  • B4 Optimized — allowed: No restriction beyond the banned list
  • B5 cEDH — allowed: No restriction beyond the banned list

Why

  • Two-card combo with March of the Machines (early with March of the Machines)

How Lotus Vault estimates a bracket

Bracket: Lotus Vault analysis, with Commander Spellbook flags

Combos

120 known combos, one of them two-card.

Combos: Commander Spellbook

Rulings

  • 2021-09-24 · Wizards of the Coast
    If you create a token that's a copy of Eloise and both are legendary, you will choose either the token or the original Eloise to keep and put the other into the graveyard. This is not the same as sacrificing it. Putting the token into the graveyard won't cause nontoken Eloise's last ability to trigger.
  • 2021-09-24 · Wizards of the Coast
    If you sacrifice a Clue token, Eloise's last ability will trigger in response. You'll surveil before drawing the card.
  • 2021-09-24 · Wizards of the Coast
    Eloise's last ability triggers whenever you sacrifice any token for any reason, not just whenever you sacrifice Clue tokens.

Rulings: Scryfall · Wizards of the Coast

Cards with the same role that fit in the same deck.